Along with making it rain, Scrooge McDuck's money swim is a definite sign of excess in success. The question is though, how much money does one need to pull off the money swim? The Billfold tackled the question and came up with a giganto number.

Using an estimate on the height of coin piles and a bit of calculus and graphing, Billfold came up with the formula y=-x2-1x+5 (where x an y is one inch). According to them:

When the area under the curve is calculated (from x=-3 to x=5), it yields roughly 46 square inches. The assumption will be made here that one cubic inch is roughly one ounce of gold. To convert that into a dome shape the value is simply cubed, which becomes 97,366 ounces. Given that 1 ounce of gold is roughly $5.00, it can extrapolated that each large pile of gold in the vault is worth $486,830.

$486,830! But if you adjust for inflation as Scrooge McDuck was first drawn in 1947 that would mean 5.2 billion dollars in one pile. And if you guesstimate how many pile are in the room, the final tally comes out to 31.2 billion dollars. That kind of money means only the six richest people in the world could pull off this stunt. Guess we should start saving. [The Billfold]

## DISCUSSION

Peter Griffin. Gold > $5 / ounce.

Did I missing anything else obvious that has already been said repeatedly in the comments below? I just want to be part of the "you're wrong" train. :-)